0.2x^2-56x+100=0

Solution for 0.2x^2-56x+100=0 equation:

0.2x^2-56x+100=0

a = 0.2; b = -56; c = +100;
Δ = b2-4ac
Δ = -562-4·0.2·100
Δ = 3056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3056}=\sqrt{16*191}=\sqrt{16}*\sqrt{191}=4\sqrt{191}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-4\sqrt{191}}{2*0.2}=\frac{56-4\sqrt{191}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+4\sqrt{191}}{2*0.2}=\frac{56+4\sqrt{191}}{0.4}
$